Infinite Limits and Sequences
Limit at Infinity
x→+∞limf(x)=A
means that
∀ε>0,∃M>0 such that ∀x∈I,x>M⇒∣f(x)−A∣<ε.
Similarly,
x→−∞limf(x)=A
means
∀ε>0,∃M>0 such that ∀x∈I,x<−M⇒∣f(x)−A∣<ε.
x→∞limf(x)=A
means
∀ε>0,∃M>0 such that ∀x∈I,∣x∣>M⇒∣f(x)−A∣<ε.
Deleted Neighborhoods
Let c be one of x0,x0+,x0−,−∞,+∞,∞. The neighborhood and deleted neighborhood of c are defined as follows:
| c | Neighborhood of c | Deleted neighborhood of c |
|---|
| x0 | An open interval J containing x0 | J∖{x0} |
| x0+ | (x0,x0+δ) | (x0,x0+δ) |
| x0− | (x0−δ,x0) | (x0−δ,x0) |
| −∞ | (−∞,b) | (−∞,b) |
| +∞ | (a,+∞) | (a,+∞) |
| ∞ | (−∞,b)∪(a,+∞) | (−∞,b)∪(a,+∞) |
General Definition of Limits
Let c be one of x0,x0+,x0−,−∞,+∞,∞, and let A be a real number or one of −∞,+∞,∞.
We say that limx→cf(x)=A iff:
For every neighborhood V of A, there exists a deleted neighborhood W of c such that for all x∈I∩W, we have f(x)∈V.
Infinite Quantities
When x→c, if f(x) grows without bound, we say f(x) is an infinite quantity (or positive/negative infinite quantity).
If
x→climf(x)=∞(i.e. x→climf(x)=+∞ or x→climf(x)=−∞),
then f(x) diverges to infinity as x approaches c.
If
x→climf(x)=A∈{−∞,+∞,∞},y→Alimg(y)=B,
then
x→climg(f(x))=B.
However, if
x→climf(x)=A,y→Alimg(y)=B∈{−∞,+∞,∞},
then
x→climg(f(x))=B
is not necessarily true.
Sequences and Their Limits
A sequence {an}n≥1 can be regarded as a function defined on the set of positive integers N∗. Hence, its limit can be defined as
n→+∞liman.
Theorems
- Let {nk}k≥1 be a strictly increasing sequence of positive integers. Define bk=ank. Then {bk}k≥1 is called a subsequence of {an}n≥1.
If
n→+∞liman=A∈R∪{−∞,+∞,∞},
then
k→+∞limank=k→+∞limbk=A.
-
Let f:(a,b)→R be a monotone non-decreasing function.
-
If f is bounded above, then
x→b−limf(x)=x∈(a,b)supf(x).
-
If f is unbounded above, then
x→b−limf(x)=+∞.
-
Let {an} be a monotone non-decreasing sequence.
-
If {an} is bounded above, then
n→+∞liman=n≥1supan.
-
If {an} is unbounded above, then
n→+∞liman=+∞.
Definition of e
Let two sequences be defined as
an=(1+n1)n,bn=(1+n1)n+1.
Then:
- an is monotonically increasing.
- bn is monotonically decreasing.
- For all n, an<bn.
- Therefore, both sequences converge and have the same limit.
We define this common limit as
e=n→+∞lim(1+n1)n.
From Discrete to Continuous
x→∞lim(1+x1)x=e.
Theorems
- x→0limxln(1+x)=1.
- x→0limxsinx=1.
- x→0limxax−1=lna.
- x→1limx−1xμ−1=μ.